5(2x^2-7)=11x

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Solution for 5(2x^2-7)=11x equation:


Simplifying
5(2x2 + -7) = 11x

Reorder the terms:
5(-7 + 2x2) = 11x
(-7 * 5 + 2x2 * 5) = 11x
(-35 + 10x2) = 11x

Solving
-35 + 10x2 = 11x

Solving for variable 'x'.

Reorder the terms:
-35 + -11x + 10x2 = 11x + -11x

Combine like terms: 11x + -11x = 0
-35 + -11x + 10x2 = 0

Factor a trinomial.
(-7 + -5x)(5 + -2x) = 0

Subproblem 1

Set the factor '(-7 + -5x)' equal to zero and attempt to solve: Simplifying -7 + -5x = 0 Solving -7 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -5x = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -5x = 0 + 7 -5x = 0 + 7 Combine like terms: 0 + 7 = 7 -5x = 7 Divide each side by '-5'. x = -1.4 Simplifying x = -1.4

Subproblem 2

Set the factor '(5 + -2x)' equal to zero and attempt to solve: Simplifying 5 + -2x = 0 Solving 5 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2x = 0 + -5 -2x = 0 + -5 Combine like terms: 0 + -5 = -5 -2x = -5 Divide each side by '-2'. x = 2.5 Simplifying x = 2.5

Solution

x = {-1.4, 2.5}

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